Development:MediaWiki TeX test: Difference between revisions

Revision as of 17:22, 24 February 2009

This should look like some maths:

$\int _{-\infty }^{\infty }e^{-x^{2}}\,dx={\sqrt {\pi }}$

(This page was created for the benefit of MDLSITE-649.)

@@ Line 1: / Line 1: @@
 This should look like some maths:
-<math>\int_{-\infty}^\infty e^{-x^5}\,dx = \sqrt{\pi} </math>
+<math>\int_{-\infty}^\infty e^{-x^2}\,dx = \sqrt{\pi} </math>
 (This page was created for the benefit of MDLSITE-649.)